10x^2-35x+24=0

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Solution for 10x^2-35x+24=0 equation:



10x^2-35x+24=0
a = 10; b = -35; c = +24;
Δ = b2-4ac
Δ = -352-4·10·24
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{265}}{2*10}=\frac{35-\sqrt{265}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{265}}{2*10}=\frac{35+\sqrt{265}}{20} $

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